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.25x^2-2x-2.75=0
a = .25; b = -2; c = -2.75;
Δ = b2-4ac
Δ = -22-4·.25·(-2.75)
Δ = 6.75
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{6.75}}{2*.25}=\frac{2-\sqrt{6.75}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{6.75}}{2*.25}=\frac{2+\sqrt{6.75}}{0.5} $
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